Question

A man walked for some distance at 8km/h and for an equal distance of 5km/h. the total time he took was 3¼ hours. Find the total distance travelled​

Answer 1

Answer:

26km

Step-by-step explanation:

let the distance walked for each = d

speed = distance/time

time = distance/speed

total time = 3.25 hrs

d/8 + d/5 = 3.25

$\frac{5d+8d}{40}=3.25$

13d = 3.25 x 40

13d = 130

d = 130/10

d=13

he walked the equal distance with both speeds

total distance = 2d

= 2 x 13

=26km

Answer 2

Answer:

20 km

Step-by-step explanation:

Let the distance travelled be '2x' Km.

For the first x km,

It's given that,

Speed = 8 Km/h

Now, we know that,

Distance = Speed × Time

=> Time = Distance/Speed

Let the time taken be t1.

Therefore, we will get,

=> t1 = x/8 hr.

Now, for the next x km,

It's given that,

Speed = 5 km/h

Let the time taken be t2.

Therefore, we will get,

=> t2 = x/5 h

Now, it's given that,

For total journey, time taken is 3¼ hr.

Therefore, we will get,

=> T = 3¼

=> t1 + t2 = (3×4+1)/4

=> x/8 + x/5 = 13/4

=> 5x/40 + 8x/40 = 13/4

=> (5x+8x)/40 = 13/4

=> 13x/40 = 13/4

=> x = 13/4 × 40/13

=> x = 1/4 × 40

=> x = 40/4

=> x = 10

Therefore, we will get,

=> 2x = 2×10

=> 2x = 20

Hence, total distance covered is 20 km.