A man walking in rain at a speed of 3kmph find rain to be falling verticall
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Let i^i^ and j^j^ be unit vector in horizontal and vertical respectively.
Let velocity of rain vr=ai^+bj^vr=ai^+bj^
speed of rain=a2+b2−−−−−−√=a2+b2
Case I:
when relative velocity of rain w.r.t man is vertical
vrm=v¯r−v¯mvrm=v¯r−v¯m
vm=3i^vm=3i^
vrm=(a−3)i^+bj^vrm=(a−3)i^+bj^
Since vrmvrm is vertical
a−3=0=>a=3a−3=0=>a=3
Case II:
when relative velocity is at 45∘45∘
v¯m=6i^v¯m=6i^
vrm=(a−6)i^+bj^vrm=(a−6)i^+bj^
=−3i^+bj^=−3i^+bj^
Since tanθ=b−3tanθ=b−3
tan 45=1
=> |b|=3|b|=3
Therefore Speed=32+32−−−−−−√=32–√Speed=32+32=32
Hence d is the correct answer.
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