A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?
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ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ-:
In ΔABC
AC² = AB² +BC²
AC² =3² + 4² ⇒AC = = 5km
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Answer:
ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ-:
In ΔABC
AC² = AB² +BC²
AC² =3² + 4² ⇒AC = \sf\sqrt{25}
25
= 5km
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