Question

a man walks 1 km. towards east then turns to south and walks 5 km. again he turns to east and walks 2 km. then he turns to north and walks 9 km. how far is he from the starting point ?

Answer 1

$\bold{Answer :}$

{ See the attachment for the path, travelled by the man }

Drawing the path, we get a triangle ODE, which is a right-angled triangle whose base is OE = 3 km and height is DE = 4 km

Therefore, the required distance of the man from its starting point is

= OD

= √(3² + 4²) km

= √(9 + 16) km

= √25 km

= 5 km

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