Question

a man walks 3 km north and then 4 km east . find how far he is now , from the starting position​

Answer 1

Answer:

It is the answer

Step-by-step explanation:

Answer 2

Answer:

Hey mate....❤❤

Here is your answer .....

He walks 3 km north , then 4 km west.

If we join all the three points , then we will observe that it is a right angle triangle.

Now the shortest distance for the startion position to the final postion is the hypotnuse

According to the pythagoras theorm,

${h}^{2} = {b}^{2} + {p}^{2}$

${h}^{2} = {4}^{2} + {3}^{2} \\ {h}^{2} = 16 + 9 \\ {h}^{2} = 25 \\ h = \sqrt{25 } \\ h = 5 \: m$

Please mark it the brainliest answer