A man walks 30 m. towards north, then 20 m. towards east and in the last 30 V2 m. towards south
- west. The displacement from origin is
(1) 10 m. towards west
(2) 10 m. towards east
(3) 60 V2 m. towards north west
(4) 60 V2 m towards east north
Answers
Answered by
3
Explanation:
Distance walked towards north = 30m
Distance walked toward south = 30√2m
Displacement in North South direction = 30√2 - 30
= 30(√2 - 1)
Distance walked in East = 20m
That would make a right angled traingle with base = 20m and perpendicular = 30(√2 - 1)
Using Pythagoras Therom,
Displacement =
√[20² + (30(√2 - 1)²) ]
= √[400 + (900(3 - 2√2)]
= √[400 + 2700 - 1800√2]
= √[3100 - 1800√2]
= 23.54 m
Answered by
3
Answer:
50m toward east
Explanation:
30j+20i+30root2[-j+i]/root2 [unit vector]
30j+20i+30i-30j
20i+30i
50i
therefore answer is 50m towards east
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