Question

a man walks 4 km due north and then 3 km due north and then 3 km due east of all will be at the end of his walk from starting.​

Answer 1

AB2+BC2=AC2

${7}^{2} + {3}^{2} = {ac}^{2}$

AC=√65

Answer 2

man walks 7km towards north and 3km due east.

Hence, after solving it by pythagoras theorem.We get distance covered by man is

$\sqrt{65 } = 8.06$

ans=8.06km