Question

a man walks 4 km /h missed the bus by 3 mins late the man walked 4 km/h reached the bus atop 3 mins early. how far is the bus stop from his house​

Answer 1

CORRECT QUESTION:

A man walks 4 km/h missed the bus by 3 mins late the man walked 5 km/h reached the bus stop 3 mins early. How far is the bus stop from his house?

ANSWER:

• The distance between the bus stop and his house = 2 km.

GIVEN:

• A man walks 4 km/h missed the bus by 3 mins late.

• The man walked 5 km/h reached the bus stop 3 mins early.

TO FIND:

• The distance between the bus stop and his house.

EXPLANATION:

Time difference = 3 - (- 3) = 6 min = 1/10 hrs.

Let the distance be x.

★ Time = Distance / speed

Time take at first time = x/4

Time take at second time = x/5

•°• 1/10 = x/4 - x/5

•°• (5x - 4x)/20 = 1/10

•°• (5x - 4x)/2 = 1

•°• 5x - 4x = 2

•°• x = 2 km.

The distance between the bus stop and his house = 2 km.

Answer 2

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★ Correct Question :

• A man walks 4 km/h missed the bus by 3 mins late the man walked 5 km/h and reached the bus stop 3 mins early. How far is the bus stop from his house?

★ Required Answer :

• Distance between the bus stop and his house is 120 km.

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★ Step by step explanation :

• Speed of man when he missed the bus by 3 mins late = 4 km/h
• Speed of man when he reached the bus stop 3 mins earlier = 5 km/h
• Time difference = 3 - (-3) = 6 mins = 1/10 hours.
• We had to find out the distance between his house and bus stop.

★ Using formula :

$\qquad\red\bigstar\:{\underline{\boxed{\bf{Time = \dfrac{Distance}{Speed}}}}}$

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★ Let :

• Distance between his house and bus stop = d km

Atq,

• In first case :

➢ㅤㅤㅤTime(1) = Distance/speed = d/4

• In second case :

➢ㅤㅤㅤTime(2) = distance/speed = d/5

Therefore,

➵ㅤㅤㅤDistance = Time(1) - Time(2)

➵ㅤㅤㅤ1/10 = d/4 - d/5

• Taking LCM :

➵ㅤㅤㅤ1/10 = (5d - 4d)/20

➵ㅤㅤㅤ1/10 × 20 = d

➵ㅤㅤㅤd = 2 km

∴ Distance between his house and bus ㅤstop = 2km

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