Question

A man walks 4 km in north and 3 km in east what is shortest distance

Answer 1

hope it helps.______

Answer 2

hi friend!

Let a man walks 4kms in North from 'A' to 'B'

and 3kms in East from 'B' to 'C'

Then the shortest distance will be AC

since, ABC is a right angled triangle,

By Pythagoras theorem AB²+BC²=AC²

=3²+4²=AC²

25=AC²

AC=5kms

I hope this will help you ;)