Question

A man walks 4m towards north then 3m towards east and there he climbs a pole of 12m height. The total displacement and distance covered by a man are. I want full solution​

Answer 1

Answer:

13 m

Explanation:

hope it will be help full

Answer 2

Answer:

distance =19m

displacement=13m

Explanation:

distance traveled by the man is the length of actual path

so distance = 4+3+12 =19m

displacement of the man is the shortest distance between his initial and final position

Let , East, North and upward direction is represented bi î,j and k respectively

then displacement of man is 3î+4j+12k

then magnitude of displacement is (3²+4²+12²)^½ or 13m

and it's direction is from initial position to final position

Hope it will help you