a man walks 6 km at 12 km per hour and returns at 10 km per hour find his average speed
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distance =6km
v(i)= 12 km/hr
t(i) = distance/velocity(i)
= 6/12
=1/2hr
v(f) = 10 km/hr
t(f) = distance/velocity(f)
=6/10 hr
average velocity= v(i) + v(f)/total time
= 12 + 10/0.5 + 0.6
= 22/1.1
= 20 km/hr
v(i)= 12 km/hr
t(i) = distance/velocity(i)
= 6/12
=1/2hr
v(f) = 10 km/hr
t(f) = distance/velocity(f)
=6/10 hr
average velocity= v(i) + v(f)/total time
= 12 + 10/0.5 + 0.6
= 22/1.1
= 20 km/hr
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