Question

A man walks 6 km to the east and then turn to the south 2 km. Again he turns to the east and walks 2 km. Next he turns northwards and walks 8 km. How far is he now from his starting point?

Answer 1

The distance between the initial and final position.

$= > \: \sqrt{ {8}^{2} + {6}^{2} }$

$= > \: \sqrt{64 + 36}$

$= > \: \sqrt{100}$

=> 10.

So, The man is 10km away from the starting position.


:-)Hope it helps u.

Answer 2

As you can see in the attachment provided by me

his net displacement is
$=\sqrt{ 8^{2} + 6^{2} }$

$=\sqrt{ 64 + 36 }$

$=\sqrt{ 100 }$

$=10km$

So, he is 10km away from hi initial position.