Question

A man walks 7 km towards north. Then he turns to east and walks 12km.after this he turns to north and walks 8km.again he turns east and walks 8km.how far is he from the starting point?

Answer 1

Answer:

25.20 km

Step-by-step explanation:

let O be the starting point,

he is far from his initial position

= √(12^2+7^2) + √(8^2 + 8^2)

= 13.89 + 11.31 = 25.20km

Answer 2

Answer:

total distance cover north = 7+8=15km

and east =12+8=20km

now distance between the starting point from last point = 20²+15²=625

625 root =25 km