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Answer:
Nice Question Ans is 2usinα/g
Explanation:
(s) in x direction s = ucosα t
(s) in y direction s = usinα t - 1/2 gt²
Time to reach highest point is half of time of flight (T) = 2usinα/g
But time for half of the path = usinα/g
Also at highest point velocity in y direction is zero.
As there is no external force acting in x-direction momentum shall be conserved. Since initial momentum in x-direction is zero because of the opp velocity vectors with identical angle Final velocity of total body in y Direction is zero.
Now it follows freely falling motion.
Since the vertical height is (S) = usinα(usina/g) - 1/2g(usinα/g)
= u²sin²α/2g
Then applying kinematics equation (since force acting on body is const)
(s)y = ut + 1/2gt²
(u=0)
u²sin²α/2g = 1/2gt²
t = usinα/g
Hence Total time taken is T = 2usinα/g
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