Question

A man walks a certain distance with certain speed. If he walks 1/2 km an hour faster, he takes 1 hour less. But, if he walks 1 km an hour slower, he takes 3 more hours. Find the distance covered by the man and his original rate of walking.

Answer 1

SOLUTION :

Let the original speed y km/ hr and total time taken be x h

Distance = xy  

[ Distance = time × speed]

(y + ½) (x - 1) = xy

xy -  y +  x/2 - ½ = xy

x/2 - y = ½ ………………(1)

[Distance covered in each case is same]

(y -1) (x + 3) = xy

xy + 3y -x -3 = xy

-x + 3y = 3……………..(2)

Multiply equation 1 by 3 ,

3x/2 - 3y = 3/2…………(3)

On adding eq 2 and 3,

-x + 3y = 3

3x/2 - 3y = 3/2

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-x +3x/2 = 3/2 +3

(-2x + 3x)/2 = (3+6)/2

x/2  = 9/2

x = 9  

On Putting x = 9 in eq 2

-x + 3y = 3

-9 + 3y = 3

3y = 3 +9

3y = 12

y = 12/3  

y = 4  

Distance covered by man = xy = 9 × 4 = 36 km

Original speed of walking = y = 4 km/h

Hence, the Distance covered by man is 36 km & Original speed of walking is 4 km/h.

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Answer 2

Step-by-step explanation:

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