Question

A man walks at 6km/h and runs at 8km/h. He covers 6km in 50min partly by running and partly by walking (1) For how long did he walk. (2) What distance did he cover walking?

Answer 1

please mark it as a brainliest answer

Answer 2

Answer:

When he walks,

Speed = 6 km/h

Distance = x km ( suppose)

Thus, the time taken by him in walking = $\frac{x}{6}$  hours,

( Because, time = distance/speed )

Now, when he runs,

Speed = 8 km/h

Distance = (6-x) km, ( Because, he covers 6 km partly by walking and partly by running )

Thus, the time taken by him in walking = $\frac{(6-x)}{8}$  hours,

Since, According to the question,

The total time taken by him in both walking and running = 50 minutes

⇒ $\frac{x}{6}+\frac{6-x}{8}=\frac{50}{60}$

⇒ $\frac{4x+18-3x}{24}=\frac{5}{6}$

⇒ $\frac{x+18}{24}=\frac{5}{6}$

⇒ $6x+108=120\implies 6x=12 \implies x =2$

Thus, The distance he covers in walking = 2 km,

And, the distance he covers in running = 6 - 2 = 4 km.