A man walks at a certain speed and reaches his destination which is 6 km in 1hr 40 minutes. if he runs the same distance in 1hr 20 minutes what is the difference in speed.
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Answer:
0.9 kmph
Step-by-step explanation:
In first case
Speed = Distance / Time
= 6 km / (1 hr 40 min)
= 6 km / (1 hr + 40/60 hr)
= 6 km / (1 hr + 2/3 hr)
= 6 km / (5/3 hr)
= [6 × 3/5] kmph
= 18/5 kmph
In second case
Speed = Distance / Time
= 6 km / (1 hr + 20 min)
= 6 km / (1 hr + 20/60 hr)
= 6 km / (1 hr + 1/3 hr)
= 6 km / (4/3 hr)
= [6 × 3/4] kmph
= 18/4 kmph
Difference in speed = 18/4 kmph - 18/5 kmph
= [18 × (1/4 - 1/5)] kmph
= [18 × (5/20 - 4/20)] kmph
= [18 × 1/20] kmph
= 9/10 kmph
= 0.9 kmph
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