a man walks at a speed 1m/s and covers a certain distance in some time . but if he walks at a speed of 3m/s, he cover an additional distance of 15 m at same time.what is the distance he actually covered?
Please guys tell me the correct answer l need it right now.
Answers
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Step-by-step explanation:
Let Distance=D; Speed= S and Time=T
In this case, Time T is the same.
Distance = Speed x Time or D= SxT
In the first case, D = 1 xT or D =T ——->(1)
In the second case, D + 15 = 3 xT or 3 T ——->(2)
Using value of D as per (1) in (2),
T +15 = 3 T or 2T =15 or T=15/2= 7.5 seconds
As D=S x T, Distance covered in first case = 1m/second x 7.5 second= 7.5 meters
(Also, Distance covered in 2nd case = 7.5 + 15 = 22.5 mteres)
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22.5meters
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