Question

a man walks at a speed 1m/s and covers a certain distance in some time . but if he walks at a speed of 3m/s, he cover an additional distance of 15 m at same time.what is the distance he actually covered?​

Answer 1

Answer:

hope.it will help you....

Answer 2

Answer:

The distance actually covered by the man is 22.5 m.

Explanation:

Given that,

Initial speed of man v= 1 m/s

Final speed of man v'= 3 m/s

Distance = 15 m

Let be the initial distance is d.

We need to calculate the distance

Using formula of speed

$v=\dfrac{d}{t}$

$d=vt$

If he walks at a speed of 3 m/s, he cover an additional distance of 15 m at same time

Using again formula of speed

$d+15=vt$...(II)

Divided equation (I) by (II)

$\dfrac{d}{d+15}=\dfrac{vt}{v't}$

put the value of v and v'

$\dfrac{d}{d+15}=\dfrac{1}{3}$

$d =7.5$

The total distance covered by the man is

$d'=d+15$

$d'=7.5+15$

$d'=22.5\ m$

Hence, The distance actually covered by the man is 22.5 m.