Physics, asked by kiaraALLC4291, 1 year ago

A man walks at a speed of 6km/hr for 1 km and 8 km/hr for next 1 km.What is the average speed of a walk of 2 km

Answers

Answered by Muskan1101
15
Here's your answer!!

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In first case,
Speed =6km/h
Distance=1km

So,
Time = D/S
 =  >  \frac{1}{6} h
In Second case,
Speed = 8km/h
Distance=1km

So,
Time =D/S
 =  >  \frac{1}{8} h
Now,
Total distance travelled=2km
Total time taken =
 =  >  \frac{1}{6} +  \frac{1}{8}   \\  =  >  \frac{4 + 3}{24}
 =  >  \frac{7}{24}
We know that,
average \: speed =  \frac{total \: distance \: travel}{total \: time}
 =  >  \frac{2 \times 24}{7}  \\  =  >  \frac{48}{7}
 =  > 6.85
Hence,
Average speed is 6.85 (approx)

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Hope it helps you !! :)

Swarup1998: Write the units also
rakeshmohata: awesome answer!!
Answered by rakeshmohata
13
Hope u like my process
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=> A man walks for 1 km with speed 6km/hr

So,

 =  >  d_{1} = 1 \:  \: km \\  \\  =  >  s_{1} = 6 \:  \: km  \:  \:  {hr}^{ - 1}  \\  \\  =  >  t_{1} =  \frac{ d_{1} }{ s_{1} }  =  \frac{1}{6}  \:  \: hr

Now,... Then he covers next 1km with a speed of 8 km/hr

So,.

  = >  d_{2} = 1 \:  \: km \\  \\  =  >  s_{2} = 8 \:  \: km  \:  \: {hr}^{ - 1}  \\  \\  =  >   t_{2} =  \frac{ d_{2}}{ s_{2}}  =  \frac{1}{8}  \:  \: hr

Thus average speed for 2 km is

 =  >  \frac{  d_{1} + d_{2} }{ t_{1} +  t_{2} }  =  \frac{1 + 1}{ \frac{1}{6} +  \frac{1}{8}  }  \\  \\  =  \frac{2}{ \frac{8 + 6}{8 \times 6} }  = 2 \times  \frac{8 \times 6}{14}  = 6.85 \: km \:  \:  {hr}^{ - 1}

Thus the required average speed = 6.85 km/hr

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Hope this is ur required answer

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