a man walks from his home to a town 6km away at 4km per hour and returns again to his home at 12km per hour using a Tonga. what is the man's average speed for the double journey
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Answered by
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d=6km
s1=4kmph
s2=12kmph
t1=6/4
=1.5s
t2=6/12
=0.5s
average speed=6×2/1.5+0.5
=12/2
=6kmph
s1=4kmph
s2=12kmph
t1=6/4
=1.5s
t2=6/12
=0.5s
average speed=6×2/1.5+0.5
=12/2
=6kmph
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