A man walks on a straight road from his home to a market 2.5km away with a speed of 5 km/h. What is the magnitude of the average velocity and average speed of the man over the interval of time
(i) 0 to 30 min
(ii) 0 to 40 min
(iii) 0 to 50 min?
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Average velocity e is equal to to average speed because when an object travels in a straight road its displacement is equals to distance
0 to 30min. Total distance/total time = 2.5 kilometre/30 minutes
2.5/1/2hour
5km/hr
Average velocity = average speed
As object is travelling in a straight line so displacement will be equal to distance
0to50min. Total distance/total time = 2.5/50
2.5/5/6
1km/hr
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it is absolutely right answer....
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