Math, asked by harsh643156, 1 year ago

cosA/1+sinA + sinA/1+cosA = 2secA

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Answered by dnavneetk9549
3

lhs

cosa/1+sina +1+sina/cosa

= cos^2a + (1+sina)^2/1+sina (cosa)

= cos^2a + 1+sin^2a +2sina/1+sina(cosa)

=cos^2a +1 +sin^2a+2sina/1+sina(cosa)

=1+1+2sina/1+sina(cosa)

=2+2sina/1+sina(cosa)

= 2( 1+sina)/ 1+sina (cosa)

= 2/ cosa

= 2seca =rhs

Answered by Anonymous
3
What dnavneetk wrote

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