A man walks on a straight road from his home to a market 2.5 km away
with a speed of 15km /h. Finding the market closed, he instantly turns and
walks back home with a speed of 17.5km/ h. What is the (a) Magnitude of
Average Velocity and (b) Average Speed of the man over the time interval 0
to 50 min?
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Answer:
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Explanation:
Let the distance between home and school = x km
Case 1
Speed = 6 km/h
Distance = x km
Time = Distance/Speed
= (x/6) hrs.
Case 2
Speed = 2 km/h
Distance = x km
Time = Distance/Speed
= (x/2) hrs.
Now, Total Distance covered by boy = 2x km
Total Time taken = x/6 + x/2
= (x + 3x)/6
= 4x/6
= (2x/3) hrs.
Avreage speed of boy = Total Distance covered / Total Time taken
= 2x/2x/3
= 2x * 3/2x
= 3 km/h
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