Question

a man walks on a straight road from his home to a market 2.5 km away with a speed of 5km/hr. finding the market closed he instantly turns and walks back home with a speed of 7.5km/hr. the average speed of the man over the interval of time 0 - 40 min is equal to?? ( i need solution)
a) 5km/hr
b) 25/4km/hr
c) 30/4km/hr
d) 45/8 km/hr

Answer 1

Answer:

45/8km/h

Explanation:

Answer 2

The correct answer is Option D ) 48/8 km/hr

A man walks from his home to market with a speed of 5 km/hr.

Distance=2.5 km

and

time = d/v = 2.5 / 5= 12hr

and he returns back with speed of 7.5 kmh in rest of time of 10 minutes.

distance= →taldistance / →taltime

=(2.5+1.25) / 40/ 60hr = 458kmhr.

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