A man was 7 times as old as his son.5 years hence the father will be 4 times as old as his son.find their present age?
Answers
Answered by
3
Let man age be. X
ND SON be Y
X=7Y
nd
X+5 = (y+5)4
X-4y=15
Put x=7y
7y -4y =15
Y=5
So x =35
Answered by
2
Son's age = X years
man's age = 7 * X years
5 years after : (7 X+5) = 4 * ( X + 5)
so 3 X = 15 => X = 5 years
child: 5 yrs man = 35 years
man's age = 7 * X years
5 years after : (7 X+5) = 4 * ( X + 5)
so 3 X = 15 => X = 5 years
child: 5 yrs man = 35 years
Similar questions