an object of height 5cm is placed perpendicular to the principle axis of a concave lens of focal length 10cm. if the distance of object from the optical centre of the lens is 20cm, determine the position, nature and size of the image formed. using lens formula?
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Distance Of Image From Lens = v = -20/3 cm.
Nature = Diminished, Virtual, Erect.
Size = 5/3 cm.
Nature = Diminished, Virtual, Erect.
Size = 5/3 cm.
akpro:
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how you have solve tell me step by step
Using the lens formula - 1/f = 1/v - 1/u
Then Using m = v/u
And then finally using m= h2/h1
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