Hindi, asked by Angelpriya80, 5 months ago

A man was murdered in his office.

The suspects are Ericson, Maggi, Joel, Benny, Sona, Patick.

A calendar found near the man has blood written 6, 4, 9, 10, 11.

Who is the killer?

A) Maggi
B) Ericson
C) Sona
D) Joel

❤️FrEe pOintS❤️❣️❣️​

Answers

Answered by TheSarcasticSmile
1

Answer:

Annelies Marie "Anne" Frank (German: [ˈanəˌliːs maˈʁiː ˈfʁaŋk], short version: [ˈanə ˈfʁaŋk] (About this soundlisten), Dutch: [ˈɑnəˌlis maːˈri ˈfrɑŋk]; 12 June 1929 – February or March 1945)[3] was a German-Dutch diarist of Jewish origin. One of the most discussed Jewish victims of the Holocaust, she gained fame posthumously with the publication of The Diary of a Young Girl (originally Het Achterhuis in Dutch; English: The Secret Annex), in which she documents her life in hiding from 1942 to 1944, during the German occupation of the Netherlands in World War II. It is one of the world's best known books and has been the basis for several plays and films.

Answered by gumnaambadshah
2

Answer:

⟹Kepler's Third Law

Johannes Kepler was a German astronomer as well as a mathematician. He gave the Three Laws of Planetary Motion.

To solve the question, we will be using the Kepler's Third Law, which states that the square of the orbital time period is proportional to the cube of the semi-major axis of the orbit.

For a circular orbit, the semi-major axis is equal to the radius.

In Mathematical Form,

\Large\boxed{\sf T^2 \propto R^3}

T

2

∝R

3

Here, we have the following data:-

• Earth

Orbital Radius = \sf R_1R

1

= 149.6 million km

Orbital Period = \sf T_1T

1

= 1.00 years

• Mars

Orbital Radius = \sf R_2R

2

Orbital Period = \sf T_2T

2

= 1.88 years

Using Kepler's Third Law, we can calculate the Orbital Radius of Mars.

\begin{gathered}\sf\displaystyle T^2\propto R^3 \\\\\\ \implies \sf \frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3} \\\\\\ \sf \implies \left(\frac{1.00}{1.88}\right)^2 = \left(\frac{149.6}{R_2}\right)^3 \\\\\\\sf \implies R_2^3 = 149.6^3 \times 1.88^2 \\\\\\ \sf\implies R_2 = \sqrt[3]{149.6^3 \times 3.5344} \\\\\\\sf \implies R_2 = 149.6 \times \sqrt[3]{3.5344} \\\\\\ \sf \implies R_2 \approx 227.878\ \textsf{million km} \\\\\\\implies \boxed{\sf R_2 \approx 227.9 \textsf{ million km}}\end{gathered}

T

2

∝R

3

T

2

2

T

1

2

=

R

2

3

R

1

3

⟹(

1.88

1.00

)

2

=(

R

2

149.6

)

3

⟹R

2

3

=149.6

3

×1.88

2

⟹R

2

=

3

149.6

3

×3.5344

⟹R

2

=149.6×

3

3.5344

⟹R

2

≈227.878 million km

R

2

≈227.9 million km

Thus, The Orbital Radius of Mars is approximately 227.9 million kilometres.

Now, we need the smallest possible distance between Mars and Earth. This can happen when the centre of Sun, Earth and Mars are all in the same line.

This is when Mars will be closest to Earth.

Consider the image attached. The smallest distance between the Earth and Mars will be \sf R_2 - R_1R

2

−R

1

If we call this smallest distance as d, then:

\begin{gathered}\sf d = R_2 - R_1 \\\\\\ \implies \sf d = \textsf{(227.9 - 149.6) million km} \\\\\\ \implies \Large\boxed{\sf d = \textsf{78.3 million km}}\end{gathered}

d=R

2

−R

1

⟹d=(227.9 - 149.6) million km

d=78.3 million km

• Thus, The Smallest Distance between Earth and Mars is about 78.3 million km.

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