A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?
(a) 1 m/s (b) 0.1 m/s
Answers
Velocity of man?
- mass of bullet = 20g = 0.02 kg
- mass of man = 80 kg
- initial velocity of bullet = 400 m/s
- initial velocity of man =0 m/s
- final velocity of bullet = 0 m/s
where,
- m - mass of bullet
- M - mass of man
- u - initial velocity of bullet
- U - initial velocity of man
- v - final velocity of bullet
- V - final velocity of man
Using Conservation of momentum,
put the value in the given formula , we get-
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Answer:
Velocity of man?
★Given⟶
mass of bullet = 20g = 0.02 kg
mass of man = 80 kg
initial velocity of bullet = 400 m/s
initial velocity of man =0 m/s
final velocity of bullet = 0 m/s
★Formula used⟶
{m\times u+M\times U=m\times v+M\times V}m×u+M×U=m×v+M×V
where,
m - mass of bullet
M - mass of man
u - initial velocity of bullet
U - initial velocity of man
v - final velocity of bullet
V - final velocity of man
★SoLution⟶
Using Conservation of momentum,
put the value in the given formula , we get-
\sf{0.02\times 400+80\times 0=0.02\times 0+80\times V}0.02×400+80×0=0.02×0+80×V
\sf {V= \dfrac{0.02\times 400+ 80 \times 0}{0.02 \times 0 +80} }V=
0.02×0+80
0.02×400+80×0
{V=\dfrac{8}{80} = 0.1}V=
80
8
=0.1
\therefore Man \ moves \ with \ a\ velocity\ of\ 0.1\ m/s
★∴Man moves with a velocity of 0.1 m/s★