d(AC)=10,d(CB)=8 and points A, B, C are collinear point. find those points whose distance will be 18.
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Answer:
ab=9
Step-by-step explanation:
ABC are collinear
a-b-c
ac=ab+bc
10=ab+8
10-8=ab
ab=2
ab=2/18
=1/9=9
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