Question

A man weighing 1500 N exerts a pressure of 105 N/m' on the ground. Calculate
his area of contact with the ground.
please answer with procedure properly
don't send useless answers or will be reported​

Answer 1

Answer:

14.29

Explanation:

Pressure = 105 N/m'

Force = 1500 N

Area = x

Presssure = force/area

=>105 = 1500/x

=>x=1500/105

=>x=14.29(approx)

Therefore,The man is touching 14.29 m^2

Answer 2

Explanation:

37%

let the amount be 100/-

amount after first discount=100-(100*30/100)=70/-

amount after second discount=70-(70*10/100)=63/-

therefore total discount=(100-63)/100=37%...Step-by-step explanation:

1) total area = ΔAED+ΔADC+ΔABC

                   = 0.5(5×10+12×6+12×7)  cm²

                   = 0.5×206 cm²

                   =103 cm²

2) total area = BCDE+ABEF

                    = (30×5 + 0.5×(20+30)×(11-5))cm²  (height of ABEF=11-5)

                    = (150 +150) cm²

                    =300 cm²

3) total area = ΔABF+ΔDCE +BFEC

                    = 2×ΔABF +BFEC        (as, ΔABF = ΔDCE)

                    = (2× 0.5 ×((22-10)/2)×(8+8) + (8+8)×10) cm²  

                                                   (as , CE=BF=8+8 , height of ΔABF =(22-10)/2)

                    =(96 +160) cm²

                    = 256 cm²