A man weighing 1500 N exerts a pressure of 105 N/m' on the ground. Calculate
his area of contact with the ground.
please answer with procedure properly
don't send useless answers or will be reported
Answers
Answer:
14.29
Explanation:
Pressure = 105 N/m'
Force = 1500 N
Area = x
Presssure = force/area
=>105 = 1500/x
=>x=1500/105
=>x=14.29(approx)
Therefore,The man is touching 14.29 m^2
Explanation:
37%
let the amount be 100/-
amount after first discount=100-(100*30/100)=70/-
amount after second discount=70-(70*10/100)=63/-
therefore total discount=(100-63)/100=37%...Step-by-step explanation:
1) total area = ΔAED+ΔADC+ΔABC
= 0.5(5×10+12×6+12×7) cm²
= 0.5×206 cm²
=103 cm²
2) total area = BCDE+ABEF
= (30×5 + 0.5×(20+30)×(11-5))cm² (height of ABEF=11-5)
= (150 +150) cm²
=300 cm²
3) total area = ΔABF+ΔDCE +BFEC
= 2×ΔABF +BFEC (as, ΔABF = ΔDCE)
= (2× 0.5 ×((22-10)/2)×(8+8) + (8+8)×10) cm²
(as , CE=BF=8+8 , height of ΔABF =(22-10)/2)
=(96 +160) cm²
= 256 cm²