Question

a man weighing 50 kgf is standing on a wooden plank 1 m× 0.5 m. what will be the pressure exerted by it on the ground ​

Answer 1

Answer:

it is 100 Pascal

p=f/a

500/0.5

100

Answer 2

Dear Student,

◆ Answer -

Pressure exerted by the man on the ground = 980 Pa

● Explanation -

Pressure exerted by the man on the ground is -

P = F / A

P = mg / lb

P = (50 × 9.8) / (1 × 0.5)

P = 490 / 0.5

P = 980 Pa

Hence, pressure exerted by the man on the ground is 980 Pa.

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