Question

A man weighing 50 kgf is standing on the floor. If area of each of his foot is 60 cm2, then find the
pressure exerted by him on the floor? (g = 9.8 m/s2)
(A) 40833.3 Pa
(B) 81666.6 Pa
(C) 0.83 Pa
(D) 8.16 Pa​

Answer 1

Answer:

(A)40833.3

Step-by-step explanation:

1 kgf = 9.8 N

50 kgf = 9.8×50=490 N

Area of one foot=60cm^2

=60÷100^2 m^2=0.006m^2(while changing from cm^2 to metre^2 we divide it by 100^2 not 100)

A person stands on two feet

So total area = 0.006×2=0.012 m^2

We know the that weight is also a force

So force exerted by man=490 N

Area=0.012 m^2

Pressure=Force÷Area

=490÷00.012

=40833.3 Pa (A)

BTW it was fiitjee big bang class 8 question,isn't it?

I also went to give it I'm in 8th class too