Physics, asked by sharanyaranjan27, 1 day ago

a man weighing 50 kgf is standing on the floor if the area of each of his foot is 60 cm^2 then find the pressure exerted by him on the floor​

Answers

Answered by lovestudies58
0

Answer:

(A)40833.3

Step-by-step explanation:

1 kgf = 9.8 N

50 kgf = 9.8×50=490 N

Area of one foot=60cm^2

=60÷100^2 m^2=0.006m^2(while changing from cm^2 to metre^2 we divide it by 100^2 not 100)

A person stands on two feet

So total area = 0.006×2-0.012 m^2

We know the that weight is also a force

So force exerted by man=490 N

Area 0.012 m^2

Pressure Force Area

=490÷00.012

=40833.3 Pa (A)

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