Question

An electric bulb draws a current of .8 A and works on 250 V on the average 8 hours a day. a. Find the power consumed by the bulb b. If the electric distribution company changes Rs 5 for 6 KWH, what is the monthly bill for 60 days​

Answer 1

Answer:

Hint:Use the formula of Power, P = VI

Step 1: Note the given values

Potential difference, V=250V

Current, I =8A

Step 2: Finding the power consumed by Bulb

Power, P= VI

Putting the values in formula:

P=250×8

P=2000watts

Bulb works on the average of 8 hours a day.

So, Power consumed in one day:

P=2000×8

P=16000Wh = 16000kWh

Hence, Power Consumed in one day is 16kWh

Step 2: Finding the monthly bill electricity.

We know that:

Power Consumed in one day is 16kWh

Power Consumed in 60 days = 60×16 kWh = 960kWh

As given,

Bill for 6kWh = Rs. 5

So, Bill for 960kWh =

6

5

×960

=

6

5

×960

= Rs. 800.

So, Bill for 1 month =

2

800

= Rs. 400

Hence, monthly bill for electricity is Rs. 400

Answer 2

Answer:

$\huge \hookrightarrow \sf \blue{question}$

An electric bulb draws a current of .8 A and works on 250 V on the average 8 hours a day. a. Find the power consumed by the bulb b. If the electric distribution company changes Rs 5 for 6 KWH, what is the monthly bill for 60 days

$\rule{200pt}{5pt}$

$\huge \dag \sf \red{ \boxed{ \blue{solution}}}$

Power of bulb=(V) = IR which is 250×0.8=200W

Energy consumed by bulb in 1 day= 200×8=1600 Wh or 1.6 Kwh

Energy consumed in 30 days = 1.6×30=48Kwh

Monthly bill= 48×3=144

Hence final answer:- Rs 144

$\rule{200pt}{5pt}$

Hope it helps you from my side

:)

An electric bulb draws a current of .8 A and works on 250 V on the average 8

hours a day. a. Find the power consumed by ...

https://brainly.in/question/50012546?

utm_source=android&utm_medium=share&utm_campaign=question