Question

A man weighing 50kg lifts a weight of 30 kg to the top of building 10m high.Find the work done by him.(take g=9.8m/s^2​

Answer 1

WORK DONE = F × S

$mg \times h$

Mass = mass of object + mass of man

30kg + 50kg = 80kg

g=9.8

h =10m

$80 \times 9.8 \times 10 = workdone$

$= 7840$

THEREFORE THE WORK DONE IS 7840 JOULES

Answer 2

The work done by the man is 2940 joules.

Explanation:

Given that,

Mass of the man, m = 50 kg

Mass of the object that is lifted by the man, m' = 30 kg

Height of the building, h = 10 m

We need to find the work done by the man. It is given by the product of force and displacement. It is given by :

$W=F\times d$

$W=m'g\times d$

$W=30\times 9.8\times 10$

W = 2940 Joules

So, the work done by the man is 2940 joules. Hence, this is the required solution.

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