A man weighing 60 kg runs along the rails with a velocity of 18 km/h and jumps into a car of mass 1 quintal (100 kg) standing on the rails. Calculate the velocity with which car will start travelling along the rails.
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Mass of man (m1) = 60kg
Initial velocity of man (u1) = 18 km/h=18x5/18=5m/s
Final velocity of man (v1) = (v2) = v
Mass of car (m2)= 100kg
Initial velocity of car (u2) = 0 (as it is in rest)
Final velocity of car (v2) = v
According to law of conservation of momentum,
m1u1 +m2u2 = m1v1 + m2v2
60x5 + 100x0 = 60 x v + 100 x v
300+0 = 160v
v = 300/160
v = 1.875 m/s
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