a man weighing 80 kg is standing in a trolley weighing 320 kg at raw the trolley is resting on frictionless horizontal race if the man starts walking on the trolley with a speed of 1 metre per second then after 4 seconds his displacement relative to the ground will be
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In 1s, man has walked, 4m/s×1s=4m, with respect to the trolley.
As position of the CoM stays same, let the distance moved by trolley be x in direction opposite to that of man.
So net diplacement of man is (4−x)m
Thus, Mman×(4−x)=Mtrolleyx
⟹80(4−x)=320x⟹x=320/400=0.8m
So net displacement of man in 1s is, 4−0.8=3.2m
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