A man weighs 300N on the surface of the earth. If he were taken to the moon his weight would be 50N. Calculate the mass of this man on Moon if g=10m/s^2
Answers
Answered by
68
Given that g on earth = 10m/s²
Weight on earth = 300 N
Weight on moon = 50 N
g on moon = unknown
Now, we know that,
weight = mass × g (acceleration due to gravity)
=> 300 = mass × 10
=> mass = 300/10
=> mass = 30 kg
Now, mass always remains constant. So mass on moon will also be 30 kg.
Answer :- 30 kg
Verification :-
g on moon is 1/6 of g on earth
=> g on moon = 1/6 × 10 = 10/6
so mass = weight/g
=> mass = 50 ÷ 10/6
=> mass = 50 × 6/10
=> mass = 30 kg.
Weight on earth = 300 N
Weight on moon = 50 N
g on moon = unknown
Now, we know that,
weight = mass × g (acceleration due to gravity)
=> 300 = mass × 10
=> mass = 300/10
=> mass = 30 kg
Now, mass always remains constant. So mass on moon will also be 30 kg.
Answer :- 30 kg
Verification :-
g on moon is 1/6 of g on earth
=> g on moon = 1/6 × 10 = 10/6
so mass = weight/g
=> mass = 50 ÷ 10/6
=> mass = 50 × 6/10
=> mass = 30 kg.
seemasonimanju:
No answer is wrong
Answer is 5kg
Correct solution is
Weight of man on earth = 300N,, g=10m/s W=mg, m=W/g, mass on earth=300/10=30kg,weight of object on moon=50N, w on moon / w on earth =1/6,,,,, soo mass on moon/mass on earth = 1/6,, mass on moon=1/6 multiply by 30 and amswer is 5 kg
I am soo sorry I was a little confused your answer is all right that was my fault Sorry your answer is right[30kg]
No problem
Answered by
17
Given that g on earth = 10m/s²
Weight on earth = 300 N
Weight on moon = 50 N
g on moon = unknown
Now, we know that,
weight = mass × g (acceleration due to gravity)
=> 300 = mass × 10
=> mass = 300/10
=> mass = 30 kg
Now, mass always remains constant. So mass on moon will also be 30 kg.
Answer :- 30 kg
Verification :-
g on moon is 1/6 of g on earth
=> g on moon = 1/6 × 10 = 10/6
so mass = weight/g
=> mass = 50 ÷ 10/6
=> mass = 50 × 6/10
=> mass = 30 kg.
Hope It Helps. ..
:)
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