A man weighs W on the surface of Earth. What is his weight at a height equal to R ? (a) W (b) W/2 (c) W/4 (d) W/8
The answer, btw, is (c)W/4.
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Weight is inversely proportional to square of distance between man and centre of earth
W ∝ 1/d^2
Initial distance when weight = W is R
When it is at a height R distance is 2R
W₁/W₂ = (d₂/d₁)^2
W/W₂ = (2R/R)^2
W/W₂ = 4
W₂ = W/4
W ∝ 1/d^2
Initial distance when weight = W is R
When it is at a height R distance is 2R
W₁/W₂ = (d₂/d₁)^2
W/W₂ = (2R/R)^2
W/W₂ = 4
W₂ = W/4
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