A man went to a place at the speed of 4km/h and came back at the speed of 16km/h .his average speed for the entire journey was?
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Answered by
1
10
km/hr is the average speed
formalae= v+u/2
=4+16/2=10km/hr
km/hr is the average speed
formalae= v+u/2
=4+16/2=10km/hr
iammrmitulp7n6ud:
bro that is incorrect
Answered by
5
Let the distance between where he is now and the place be : x
Speed 1 : 4km/hr
Speed 2: 16km/hr
Time 1 : x/4
Time 2: x/16
Total Time :
![\frac{x}{4} + \frac{x}{16} = \frac{5x}{16} \frac{x}{4} + \frac{x}{16} = \frac{5x}{16}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B4%7D++%2B++%5Cfrac%7Bx%7D%7B16%7D++%3D++%5Cfrac%7B5x%7D%7B16%7D+)
Total distance = x + x = 2x
AVG SPEED = 2x ÷ 5x/16
= 32/5
= 6.4 km/hr
Speed 1 : 4km/hr
Speed 2: 16km/hr
Time 1 : x/4
Time 2: x/16
Total Time :
Total distance = x + x = 2x
AVG SPEED = 2x ÷ 5x/16
= 32/5
= 6.4 km/hr
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