A man when he travels at 3 kmph he reaches the station 2 mins late. However when he travels at 4 kmph he reaches 2 mins quick. Find the distance the man has to travel?
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Answer:
d = s x t ( t = X)
d = 3X +6
d = 4x-8
d = 3x +6=4x-8
4x-3x=8+6
x=14
d=3*14+6
d=36
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