Question

A man when he travels at 3 kmph he reaches the station 2 mins late. However when he travels at 4 kmph he reaches 2 mins quick. Find the distance the man has to travel?

Answer 1

Answer:

d = s  x  t ( t = X)

d =  3X +6

d = 4x-8

d = 3x +6=4x-8

4x-3x=8+6

x=14

d=3*14+6

d=36