Math, asked by delisha482, 4 days ago

A man who can who can swim 33 m minutes in Stillwater swims 4440 m against the current and four 440 m with the current if the difference between those two times is 10 m what is the speed of the current option 811 and 11 meter minutes 33 minute today metres minutes 23 m minutes 5.5 m minutes

Answers

Answered by salahuddeenr2008
1

Answer:

Let speed of current be x m/ minute

UPSTREAM SPEED = {48-x} m/ minute

DOWNSTREAM SPEED = {48+x} m/ minute

200/{48-x} - 200/{48+x} = 10

200{48+x} - 200{48-x} = 10{48+x}{48-x}

10x^2 +400x - 23040=0

x^ +40x = 2304

ADD 400

x^ +40x +400 = 2704

{x + 20}^2 = 2704

x = 52–20 =32m/ minute ANSWER

Step-by-step explanation:

Answered by ItzSavageGirlIsha
7

Step-by-step explanation:

Let X m/ min be the speed of the current.

Time taken against current=200/48-x

Time taken with the current=200/48+X

Difference=10 min

(200/48-x)-(200/48+X)=10

200(48+X)-200(48-x)/48^2-x^2=10

200(48+x-48+X)/…=10

400x/…=10

48^2-x^2)10=400x

2304-x^2=40x

X^2+40x-2304=0

it's Isha

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