Question

A man who is 45 years old has a son whose age is 15. In how many years will the man be twice as his son?

Answer 1

Present age of man= 45yrs

Present age of his son= 15yrs

let the no. of years for the man to become 2times his son be "x"

Now, A/Q we get,

45+x= 2(15+x)

=>45+x= 30+2x

=>45-30=2x-x

=>15=x

=>x=15

Therefore, after 15 years the man will be twice as his son!