Question

A man who raises in mass M to a height H and then shifts it horizontally over the distance x find the total work done against the force of gravity

Answer 1

At height h, PE of man = mgh

When he walks over the distance x horizontally, there is no change in PE of the body.

Work done = Force*displacement

But, PE is constant hence, force is zero

Thus, Work done against gravity is zero.

Answer 2

Answer:

the man pulls the object perpendicularly therefore workdone is zero.