Math, asked by skbisht4807, 6 months ago

A man wishes to buy few masks. There are two types of masks, type-A cost 11 rupees per mask and type-B cost 13 rupees per mask. Given that the man has a total of 369 rupees, in how many ways can he buy masks of both categories?

Answers

Answered by arpitpandey52
0

Step-by-step explanation:

1mask =11

1mask=13rs

of mask=11 can buy =4

2nd mask=13rs buy=25

11*4=44

13*25=325

325+44

369ans

Answered by vinod04jangid
0

Answer:

he buy masks of both categories in 3 ways

(30 , 3)  , ( 17 , 14)  & ( 4 , 25)

Step-by-step explanation:

Solution:

type-A cost 11 rupees per mask  - Quantity = A

type-B cost 13 rupees per mask  - Quantity = B

all money has to be spend

given ;

11A  + 13B =  369

= 11A + 11B + 2B = 11 * 33  + 6

= 2B = 11 ( 33 - A - B )  +  6

= 2(B - 3)  = 11 (33 - A - B)

2 & 11 are prime

Hence  B - 3 must a factor of 11

B - 3  =  0

 => B  = 3   , A  = 30

B - 3 =  11

=>  B = 14  ,   A  = 17

B - 3 = 22

=> B = 25   , A =  4

Three ways

(30 , 3)  , ( 17 , 14)  & ( 4 , 25)    

#SPJ2

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