Question

A man works twice as fast as a woman.a woman works twice as fast as child.if 16 men can complete job in 16 days.hiw many days would require 32 womdn and 64 childreN together to complete work

Answer 1

Step-by-step explanation:

Eff ratio of M:W:C=4:2:1

Total work=(16×4)×16

Required days=(16×4)×16/(32×2+64)=16 days

solution Magic of Math(MoM)

Answer 2

They can complete the work together in 8 days.

Step-by-step explanation:

A man works twice as fast as a woman and a woman works twice as fast as  child.

∵ 16 men can complete a job in 16 days

∴ 32 women can complete the same job in = 16 days

∴ 64 children can complete the same job in = 16 days

work of one day done by 32 women = $\frac{1}{16}$

work of one day done by 64 children = $\frac{1}{16}$

work of one day done by together 32 women and 64 children = $\frac{1}{16} +\frac{1}{16}$

                                                                                                        = $\frac{2}{16}$

                                                                                                       $=\frac{1}{8}$

They can complete the work together in 8 days.

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