Question

A man works twice as fast as a woman. A woman works twice as fast as a child. If 8 men can complete a job in 11 days how many days would be required for 12 women and 8 children together to complete the same job?​

Answer 1

Answer:

less

Step-by-step explanation:

less than the man took to complete

Answer 2

11 days would be required for 12 women and 8 children together to complete the same job which can be completed by 8 men in 11 days.

Given,

A man works twice as fast as a woman and a woman works twice as fast as a child.

To find,

The number of days required for 12 women and 8 children together to complete the same job which can be completed by 8 men in 11 days

Solution,

The method of finding the number of days required for 12 women and 8 children together to complete the same job is as follows -

Since a man works twice as fast as a woman, work done by 6 men is equivalent to the work done by 12 women on the same number of days.

Since a woman works twice as fast as a child, work done by 4 women is equivalent to the work done by 8 children on the same number of days.

Since a man works twice as fast as a woman, work done by 2 men is equivalent to the work done by 4 women on the same number of days.

So, the total work of 12 women and 8 children is equivalent to the work done by $6+2=8$ men on the same number of days. So the days required for 12 women and 8 children to do the same work will be 11 days as well.

Hence, 11 days would be required for 12 women and 8 children together to complete the same job which can be completed by 8 men in 11 days.

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