Question

A man 'x' walking on the road has mass of 40kg and velocity 0.5 m/s. Another man 'y' running on the road has mass double that of 'x' but his velocity is same as 'x'. Calculate the kinetic energy of 'y'.

Pls answer it fast today is my exam. So, pls fast.

Answer 1

A.T.Q - velocity of y = velocity of x = 0.5m/s

mass of y = 2*mass of x = 2*40 = 80kg

kinetic energy= 1/2* mv²

=

$1 \div 2 \times 80 \times {0.5}^{2}$

10 Joules