Question

a manhas only 20 paise coins and 25 paise coins in his purse if he has 50 coins in all totalling rupees 11.25 how many coins of its kind does he have and draw the graph​

Answer 1

Answer:

20 paise coin =25

25 paise coin=25

Step-by-step explanation:

take 20 and 25 paise coins as x and y

x+y=50........(1)

20x+25y=1125  (11.25 Rs converted into paise).........(2)

solve 1 and 2 we get x=25 y=25

Answer 2

$\bold \color{green} { \underline { \underline \red{ \green\star \: required \: answer}}} \star$

Let the number of 20 paisa coins be x and that of 25 paisa coins be y. then,

$\bold{x + y = 50}$

total value of 20 paisa coins = 20x paisa

total value of 25 paisa coins = 25y paisa

$\bold{so \: that \: \: 20x + 25y = 1125 }\\ \bold{ \implies4x + 5y - 225 = 0}$

now by using corss-multiplication, we have

$\bold{\frac{x}{ - 225 + 150} = \frac{ - y}{ - 225 + 20} = \frac{1}{5 - 4} }$

$\bold{\implies \frac{x}{25} = \frac{y}{25} = \frac{1}{1}}$

$\bold{\implies \: x = 25 \: \: and \: y = 25}$

hence, there are 25 coins of each kind..